Math

Here is how we think about it: It is $ nose candy for the first 10 feet. After that it is $25 for each pass onitional 10 feet. This tells us that it is arithmetic sequence because we are multiplying. N= the bend of origination altogetherN= 8 D= the common differenceD=25 A1= the first frontierA1= light speed An= the second termAn= a8 Next, we contract to count on what a8 is. An= a8+ (n-1) d A8= 100+ (8-1)25 A8=100+7(25) A8=100+200 A8=300 Now that we crawl in what A8 is, we ingest to know what the sum of the sequence is from A1 to A8. Sn= n (a1+a8) over2 S8= 8(100+300) over2 S8= 8(400) over2 S8= 4(400) = 1600 Thus, the hail to build a 90 foot CB lift is $1600. A person deposited $500 in a nest egg depict that pays %5 annual interests that is compounded twelvemonthly. At the obliterate of 10 classs, how ofttimes money will be in the savings visor? Here is how we think about it: each(prenominal) twelvemonth 5% of the equalizer is hyperkinetic sy ndromeed to the balance. If we let B= the balance, it would aim like: B+ (.05) B B (1+.05) B (1.05) In other words, each year the existing balance is calculate by 1.05. This repeated extension by the same number tells us we have a geometric sequence. First, we need to identify.

N= the number of termsN= 10 R= the common ratioR= 1.05 A1= the first termA1= 500(1.05) =525 the balance at the end of 1 year In a savings account, the total balances at the end of each year form the sequence, so we dont need to add up all the terms in the sequence. We just need to find out what the balance is at the end of 10 years, so we ar e look for the value of A10. An= a1 (rn-1)! A10=525(1.05) square objet dart of 9 A10= 525(1.55134) A10=814.46 Thus, the balance in the savings account at the end of 10 years will be 814.46. References:Mat126 math in our World Bluman,1sted, Ashford assignment guideIf you want to get a in force(p) essay, order it on our website: OrderCustomPaper.com

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